Chapter 1 · Principles of Electricity

1.8Electrical Equations

Power and energy

Example 1.4. A 12 V motor draws 0.5 A. P = 12 × 0.5 = 6 W. In 2 hours it uses E = 6 × 2 = 12 Wh = 0.012 kWh.

Resistors in series (same current, voltages add): Rtotal = R1 + R2 + R3 + ...

Resistors in parallel (same voltage, currents add): 1 / Rtotal = 1/R1 + 1/R2 + 1/R3 + ... For two resistors: Rtotal = (R1 × R2) / (R1 + R2).

Seriessame current, voltages addR1R2R3R = R1 + R2 + R3Parallelsame voltage, currents addR1R2R = R1R2 / (R1 + R2)Voltage dividerVinR1R2VoutVout = Vin·R2/(R1+R2)
Series, parallel and voltage divider circuits

Example 1.5. 100 Ω and 300 Ω in parallel: R = (100 × 300) / 400 = 75 Ω.

Voltage divider (used with many sensors): Vout = Vin × R2 / (R1 + R2)

Example 1.6. Vin = 5 V, R1 = 10 kΩ, R2 = 10 kΩ. Vout = 5 × 10 / 20 = 2.5 V.

Kirchhoff's laws